module AufgabeFFP8 where import Data.Array import Data.List hiding ((\\)) import Test.QuickCheck type Nat = Int -- Minfree basic version minfree_bv :: [Int] -> Int minfree_bv xs = head ([0..] \\ xs) (\\) :: Eq a => [a] -> [a] -> [a] xs \\ ys = filter (\x -> x `notElem` ys) xs -- Minfree checklist minfree_chl :: [Int] -> Int minfree_chl = search . checklist search :: Array Int Bool -> Int search = length . takeWhile id . elems checklist :: [Int] -> Array Int Bool checklist xs = accumArray (||) False (0,n) (zip (filter (<=n) xs) (repeat True)) where n = length xs -- minfree countlist minfree_col :: [Int] -> Int minfree_col = search0 . assocs . countlist countlist :: [Int] -> Array Int Int countlist xs = accumArray (+) 0 (0,n) (zip xs (repeat 1)) where n = length xs sort :: [Int] -> [Int] sort xs = concat [replicate k x | (x,k) <- assocs $ countlist xs] search0 :: [(Int, Int)] -> Int search0 [] = -1 search0((i,0):_) = i search0 (x:xs) = search0 xs -- minfree basic daq minfree_b :: [Int] -> Int minfree_b xs = if (null ([0..b-1] \\ us)) then (head ([b..] \\ vs)) else (head ([0..] \\ us)) where b = 1 + (length xs) `div` 2 (us, vs) = partition ( Int minfree_r = minfrom_r 0 minfrom_r :: Nat -> [Nat] -> Nat minfrom_r a xs | null xs = a | length us == b-a = minfrom_r b vs | otherwise = minfrom_r b us where b = a + 1 + (length xs) `div` 2 (us, vs) = partition ( Int minfree_o xs = minfrom_o 0 (length xs, xs) minfrom_o :: Int -> (Int, [Int]) -> Int minfrom_o a (n, xs) | n == 0 = a | m == b-a = minfrom_o b (n-m, vs) | otherwise = minfrom_o a (m, us) where (us,vs) = partition (Bool) -> (p->s) ->(p-> [p]) -> (p-> [s] -> s)-> p -> s divideAndConquer indiv solve divide combine initPb = dAC initPb where dAC pb | indiv pb = solve pb | otherwise = combine pb (map dAC (divide pb)) -- minfree basic daq higher order b_indiv :: Int -> [Int] -> Bool b_indiv l xs = length xs < l b_solve :: [Int] -> [Int] b_solve = id b_divide :: Int -> [Int] -> [[Int]] b_divide b xs = [us, vs] where (us,vs) = partition ( [Int] -> [[Int]] -> [Int] b_combine b _ (us:vs:[]) = if (null ([0..b-1] \\ us)) then ([b..] \\ vs) else ([0..] \\ us) minfree_bhof :: [Int] -> Int minfree_bhof xs = head $ divideAndConquer (b_indiv (length xs)) b_solve (b_divide b) (b_combine b) xs where b = 1+(length xs) `div` 2 -- minfree refined daq higher order -- refined divide-and-conquer mittels higher order function --minfree_rhof :: [Int] -> Int --minfree_rhof = divideAndConquer r_indiv r_solve r_divide r_combine -- --r_indiv :: (Int, [Int]) -> Bool --r_indiv (a, xs) -- optimised divide-and-conquer mittels higher order function --minfree_ohof :: [Int] -> Int -- QuickCheck part functions = [ minfree_bv, minfree_chl, minfree_col, minfree_b, minfree_r, minfree_o, minfree_bhof] -- calc values of all function calc_all :: [Int] -> [Int] calc_all xs = [ f xs | f <- functions ] -- check if all values of a list are the same all_eq :: [Int] -> Bool all_eq (x:[]) = True all_eq (x:y:xs) | x == y = all_eq (y:xs) | otherwise = False -- check if a list contains no duplicates --no_dups :: [Int] -> Bool --no_dups [] = True --no_dups (x:xs) -- | x `elem` xs = False -- | otherwise = no_dups xs prop_allImplsEq_a :: [Int] -> Bool prop_allImplsEq_a xs = all_eq $ calc_all (nub xs) -- keine negativen listenelemented durch vorbedingung entfernt prop_allImplsEq_b :: [Int] -> Property prop_allImplsEq_b xs = all (>=0) xs ==> all_eq $ calc_all (nub xs)